3.1.53 \(\int \frac {x^5}{(b x^2)^{5/2}} \, dx\) [53]

Optimal. Leaf size=16 \[ \frac {x^2}{b^2 \sqrt {b x^2}} \]

[Out]

x^2/b^2/(b*x^2)^(1/2)

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Rubi [A]
time = 0.00, antiderivative size = 16, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {15, 8} \begin {gather*} \frac {x^2}{b^2 \sqrt {b x^2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^5/(b*x^2)^(5/2),x]

[Out]

x^2/(b^2*Sqrt[b*x^2])

Rule 8

Int[a_, x_Symbol] :> Simp[a*x, x] /; FreeQ[a, x]

Rule 15

Int[(u_.)*((a_.)*(x_)^(n_))^(m_), x_Symbol] :> Dist[a^IntPart[m]*((a*x^n)^FracPart[m]/x^(n*FracPart[m])), Int[
u*x^(m*n), x], x] /; FreeQ[{a, m, n}, x] &&  !IntegerQ[m]

Rubi steps

\begin {align*} \int \frac {x^5}{\left (b x^2\right )^{5/2}} \, dx &=\frac {x \int 1 \, dx}{b^2 \sqrt {b x^2}}\\ &=\frac {x^2}{b^2 \sqrt {b x^2}}\\ \end {align*}

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Mathematica [A]
time = 0.00, size = 13, normalized size = 0.81 \begin {gather*} \frac {x^6}{\left (b x^2\right )^{5/2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^5/(b*x^2)^(5/2),x]

[Out]

x^6/(b*x^2)^(5/2)

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Maple [A]
time = 0.02, size = 12, normalized size = 0.75

method	result	size
default	\(\frac {x^{6}}{\left (b \,x^{2}\right )^{\frac {5}{2}}}\)	\(12\)
risch	\(\frac {x^{2}}{b^{2} \sqrt {b \,x^{2}}}\)	\(15\)
trager	\(\frac {\left (x -1\right ) \sqrt {b \,x^{2}}}{b^{3} x}\)	\(18\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^5/(b*x^2)^(5/2),x,method=_RETURNVERBOSE)

[Out]

x^6/(b*x^2)^(5/2)

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Maxima [A]
time = 0.28, size = 14, normalized size = 0.88 \begin {gather*} \frac {x^{4}}{\left (b x^{2}\right )^{\frac {3}{2}} b} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^5/(b*x^2)^(5/2),x, algorithm="maxima")

[Out]

x^4/((b*x^2)^(3/2)*b)

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Fricas [A]
time = 0.34, size = 11, normalized size = 0.69 \begin {gather*} \frac {\sqrt {b x^{2}}}{b^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^5/(b*x^2)^(5/2),x, algorithm="fricas")

[Out]

sqrt(b*x^2)/b^3

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Sympy [A]
time = 0.25, size = 10, normalized size = 0.62 \begin {gather*} \frac {x^{6}}{\left (b x^{2}\right )^{\frac {5}{2}}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**5/(b*x**2)**(5/2),x)

[Out]

x**6/(b*x**2)**(5/2)

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Giac [A]
time = 1.43, size = 9, normalized size = 0.56 \begin {gather*} \frac {x}{b^{\frac {5}{2}} \mathrm {sgn}\left (x\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^5/(b*x^2)^(5/2),x, algorithm="giac")

[Out]

x/(b^(5/2)*sgn(x))

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Mupad [B]
time = 0.96, size = 6, normalized size = 0.38 \begin {gather*} \frac {\left |x\right |}{b^{5/2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^5/(b*x^2)^(5/2),x)

[Out]

abs(x)/b^(5/2)

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